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's (2014) questionnaire. Next, we analyze and discuss a conspicuous difference between first-year and master students in the data of Hoekstra et al., which is CAL-101 research buy consistent with the notion that master students may have used knowledge of CIs to disambiguate nominally incorrect items and identify them as correct statements. Finally, we describe our extension and discuss the results. Two correct interpretations of a CI The theory from which CIs are derived and the ensuing properties of CIs permit two interpretations that we will separately describe and discuss next. One is in the context of significance testing; the other is in the context of parameter estimation. With such correct interpretations in mind, we will close this section with a discussion of the resultant difficulty to infer misinterpretation of CIs from endorsement of the items in the questionnaire of Hoekstra et al. (2014). The CI as the range of point hypotheses that the current data will not reject in a size-�� test The expressions with which the upper and lower limits of the CI for a distributional parameter are computed emanate from the setup of a significance test for that parameter. The link holds for any parameter but, for simplicity, take the case of a single mean in the usual conditions of unknown population variance. In a two-sided size-�� test of the null hypothesis H0: Afatinib purchase �� = ��0 against the alternative H1: �� �� ��0, the null is not rejected if it so happens that tn?1,��/2 is correct (i.e., if the true value of the population mean is ��0), rendering the desired size-�� test. It is important to notice that T in Equation (1) is a random variable and, then, Equation (1) represents a statement about the probability that such a random variable lies within the stated limits. One can thus wonder about the set of hypotheses (i.e., values of ��0) that the Sitaxentan current data would not reject. Rather than repeatedly computing T for different values of ��0 and checking against the limits for rejection, one can manipulate Equation (1) algebraically to arrive at Prob(X??sxntn?1,1?��/2